Refer to the diagram shown below.
Given:
m₁ = 8.47 kg, the mass of the bicycle frame
m₂ = 0.82 kg. the mass of each wheel
r = 0.343 m, the radius of each wheel
v = 3.55 m/s, forward velocity.
The moment of inertia of each wheel is
I = (1/2)*m₂*r² = 0.5*(0.82 kg)*(0.343 m)² = 0.048224 kg-m²
The angular velocity of each wheel is
ω = (3.55 m/s)/(0.343 m) = 10.35 rad/s
The kinetic energy of the bicycle is
KE = (1/2)*m₁*v² + 2*(1/2)*I*ω²)
= 0.5*(8.47 kg)*(3.55 m/s)² + (0.048224 kg-m²)*(10.35 rad/s)²
= 58.5375 J
Answer: 58.54 J
