Answer:
P.E=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)
Explanation:
What is the potential energy of the two-spring system after the point of connection has been moved to position (x, y)? keep in mind that the unstretched length of each spring ℓ is much less than l and can be ignored (i.e., ℓ≪l). express the potential in terms of k, x, y, and l?
potential energy is equal to the kinetic energy
potential energy is energy at rest while kinetic energy is energy due to motion
P=U
P=1/2k((-L – x)^2 + (L – x)^2 + 2(-y)^2)
k=elastic constant of the pring system
x,y are the position
