Respuesta :
let the smallest one be x, the second one is then x+1, the third one is x+2
x+(x+1)+(x+2)=114
3x+3=114
3x=111
x=37
the three consecutive integers are: 37,38,39
x+(x+1)+(x+2)=114
3x+3=114
3x=111
x=37
the three consecutive integers are: 37,38,39
Our three consecutive integers are 37, 38, and 39.
Work is provided in the image attached.
