Respuesta :
To find the magnitude of the resultant vector, the formula is written as:
R² = x² + y²,
where
x and y are the perpendicular vectors along x and y axes, respectively.
So, any pair of x and y must satisfy the given equation. There are a lot os possibilities. Let's say, if x = 12, then,
20² = 12² + y²
y = 16
One answer would be a horizontal x vector equal to 12 m, and a vertical y vector equal to 16 m.
R² = x² + y²,
where
x and y are the perpendicular vectors along x and y axes, respectively.
So, any pair of x and y must satisfy the given equation. There are a lot os possibilities. Let's say, if x = 12, then,
20² = 12² + y²
y = 16
One answer would be a horizontal x vector equal to 12 m, and a vertical y vector equal to 16 m.
The resultant perpendicular components can be written as [tex]R^2_x+R^2_y=400[/tex].
The resultant of the two perpendicular vectors is given as
[tex]R^2=R^2_x+R^2_y[/tex] where, [tex]R_x[/tex] is the horizontal component and [tex]R_y[/tex] is the vertical component.
According to the question, the resultant magnitude of the vector is [tex]20\;meters[/tex]. So,
The resultant perpendicular components can be written as
[tex]R^2_x+R^2_y=R^2\\R^2_x+R^2_y=400[/tex]
Learn more about vectors here:
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