Respuesta :
The diameter of Venus (from tables) is 12,100 km.
Therefore its radius is
r = 12100/2 = 6050 km = 6050 x 10³ m = 6.05 x 10⁶ m
The layer of gas is 50 km thick.
The outer radius of the surrounding layer of gas is
R = r + 50 x 10³ m
= 6.05 x 10⁶ + 50 x 10³ m
= 6.1 x 10⁶ m
The volume of the layer of gas is
V = [(4π)*3] * [(6.1 x 10⁶)³ - (6.05 x 10⁶)³] m³
= [(4π)/3] * 5.535875 x 10¹⁸ m³
= 2.318862 x 10¹⁹ m³
Because the density of the gas layer is 21 kg/m³, therefore the mass of the gas layer is
m = (21 kg/m³) * (2.318862 x 10¹⁹ m³)
= 4.8696 x 10²⁰ kg
Answer: [tex]4.8696 \times 10^{20} \, kg[/tex]
Therefore its radius is
r = 12100/2 = 6050 km = 6050 x 10³ m = 6.05 x 10⁶ m
The layer of gas is 50 km thick.
The outer radius of the surrounding layer of gas is
R = r + 50 x 10³ m
= 6.05 x 10⁶ + 50 x 10³ m
= 6.1 x 10⁶ m
The volume of the layer of gas is
V = [(4π)*3] * [(6.1 x 10⁶)³ - (6.05 x 10⁶)³] m³
= [(4π)/3] * 5.535875 x 10¹⁸ m³
= 2.318862 x 10¹⁹ m³
Because the density of the gas layer is 21 kg/m³, therefore the mass of the gas layer is
m = (21 kg/m³) * (2.318862 x 10¹⁹ m³)
= 4.8696 x 10²⁰ kg
Answer: [tex]4.8696 \times 10^{20} \, kg[/tex]
4.9x10^20 kg
Venus has a radius of 6051.8 km, so we'll assume the total volume of the atmosphere is the volume of a sphere with a radius of (6051.8 + 50) km minus the volume of Venus itself. So
V = 4/3 pi r^3
6051.8 + 50 = 6101.8
The overall expression is
V = 4/3 pi 6101.8^3 - 4/3 pi 6051.8^3
V = 4/3 pi (6101.8^3 - 6051.8^3)
V = 4/3 pi 5539155986
V = 23202362337
V = 2.32x10^10 km^3
V = 2.32x10^19 m^3
Now multiply the volume by the density. So
V = 2.32x10^19 m^3 * 21 kg/m^3 = 4.87x10^20 kg
So the atmosphere of Venus has a mass of about 4.9x10^20 kg