Which graph represents the function p(x) = |x – 1|?

Answer: The correct option is fourth option.
Explanation:
The given function is,
p(x)=|x-1|
The graph of the given function is a transformed form of f(x)=|x|.
The parent modulus function is,
P(x)=|x+a|+b
If a>0, then graph shifts left by a units and if a<0, then graph shifts right by a units.
If b>0, then graph shifts upward by b units and if b<0, then graph shifts downward by b units.
Since the value of a is -1 and value of b is 0, therefore the graph of f(x)=|x| shifts right side by 1 unit.
Hence the fourth option is correct.
Other way to choose the correct option is find the x intercept and y intercept.
Put x=0
P(x)=|0-1|= -1
So y-intercept is (0,-1)
Put p(x)=0
0=|x-1|
x=1
So, the x-intercept is (1,0).
From x and y-intercepts, we can say that the fourth option is correct.
Answer:
Fourth graph represent the function p(x) = |x – 1|.
Step-by-step explanation:
Given : Function p(x) = |x – 1|.
To find : Graph .
Solution : We have given that Function p(x) = |x – 1|.
The graph of the given function is a transformed form of f(x)=|x|.
By the transformation rule f(x-h) graph would be shifted to right by h units.
Since , grapf of function f(x)=|x| became shifted to 1 unit right.
Therefore , fourth graph represent the function p(x) = |x – 1|.