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Diethyl ether is produced from ethanol according to the following equation:

2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

Calculate the percent yield if 76.1 g of ethanol reacts to produce 22.1 g of ether.

Respuesta :

Edufirst
2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(l)

1) molar ratios

2 moles CH3CH2OH : 1 mol CH3CH2OCH2CH3

3) convert 76.1 g of ethanol to number of moles

number of moles = mass in grams / molar mass

molar mass of CH3CH2OH = 2 * 12 g/mol + 6 * 1 g/mol + 16 g/mol = 46 g/mol

number of moles = 76.1 g / 46 g/mol = 1.654 mol

4) calculate theoretical yield: 

2 moles CH3CH2OH / 1 mol CH3CH2OCH2CH3 = 1.65 mol CH3CH2OH / x

=> x = 1.654 / 2 = 0.827 mol CH3CH2OCH2CH3

5) calculate the number of moles in 22.1g of ether

number of moles = mass in grams / molar mass

molar mass of ether = 4*12g/mol + 10*1 g/mol + 16g/mol = 74 g/mol

number of moles of ether = 22.1 g / 74 g/mol = 0.299 moles

6) Percent yield = [actual yield /  theoretical yield] * 100 = [0.299 / 0.827] * 100 = 36.15%

Answer: 36.2%

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