Respuesta :
[tex]\bf \begin{array}{llccll}
y=&{{ -4}}j^2&{{ +3}}j&{{ -28}}\\
&~\uparrow &\uparrow &\uparrow \\
&~a&b&c
\end{array}
\\\\\\
discriminant\implies b^2-4ac=
\begin{cases}
0&\textit{one solution}\\
positive&\textit{two solutions}\\
negative&\textit{no solution}
\end{cases}[/tex]
so.. check what value the discriminant is then.
so.. check what value the discriminant is then.
Answer with Step-by-step explanation:
We know that the discriminant(d) of a quadratic equation ax²+bx+c=0 is given by:
d=b²-4ac
Also, if d=0 then we have two equal real roots
if d is positive i.e. d>0 then, we have two unequal real roots
and when d is negative i.e. d<0 then, we have no real root
Here, We are given equation -4j²+3j-28
a= -4
b=3
and c= -28
So, d=(3)²- 4×(-4)×(-28)
d= 9-448
d= -439
d<0
Hence, equation -4j²+3j-28 has no real roots
