Answer:
[tex]a_n = 25+3(n-1)[/tex]
[tex]a_{12}=58[/tex]
Step-by-step explanation:
Given the functions:
[tex]f(n) = 25[/tex] and [tex]g(n) = 3(n-1)[/tex]
Now, combine them to create an arithmetic sequence i,.e, [tex]a_n[/tex]
⇒[tex]a_n = f(n)+g(n)[/tex]
then;
[tex]a_n = 25+3(n-1)[/tex] ....[1]
We have to find the 12th term;
Substitute n = 12 in [1] we have;
[tex]a_{12} = 25+3(12-1)[/tex]
⇒[tex]a_{12} = 25+3(11)[/tex]
⇒[tex]a_{12} = 25+33 = 58[/tex]
Therefore, the 12th term is 58
