Respuesta :
1. 2x + 3y = 16....just a matter of subbing...answer is (5,2) <=
2. to find the x int, sub in 0 for y and solve for x
-2x + 5(0) = -20
x = -20/-2
x = 10......or (10,0) <=
3. (2,-5)(4,1)...using slope formula : (y2 - y1) / (x2 - x1)
slope = (1 - (-5) / (4 - 2) = 6/2 = 3 <=
4. y = 4x - 3....the first 3 are true
2. to find the x int, sub in 0 for y and solve for x
-2x + 5(0) = -20
x = -20/-2
x = 10......or (10,0) <=
3. (2,-5)(4,1)...using slope formula : (y2 - y1) / (x2 - x1)
slope = (1 - (-5) / (4 - 2) = 6/2 = 3 <=
4. y = 4x - 3....the first 3 are true
Part 1) Which ordered pair is a solution to this equation?
[tex] 2x + 3y = 16 [/tex]
Substitute the values of each pair ordered in the equation to find the solution
A. [tex] (5, 2) [/tex]
[tex] 2*5 + 3*2 = 10+6\\ 16=16 [/tex]
The pair ordered A is a solution
B. [tex] (3, 2) [/tex]
[tex] 2*3 + 3*2 = 6+6 [/tex]
[tex] 12\neq 16 [/tex]
The pair ordered B is not a solution
C. [tex] (11, 1) [/tex]
[tex] 2*11 + 3*1 = 22+3 [/tex]
[tex] 25\neq 16 [/tex]
The pair ordered C is not a solution
D. [tex] (7, 2) [/tex]
[tex] 2*7 + 3*2 = 14+6 [/tex]
[tex] 20\neq 16 [/tex]
The pair ordered D is not a solution
therefore
the answer part 1) is
The ordered pair A. [tex] (5, 2) [/tex] is a solution of the equation
Part 2) The equation of a line is [tex] -2x+5y=-20 [/tex]
we know that
the x-intercept is when the value of y is equal to zero
so
for [tex] y=0 [/tex]
Find the value of x
substitute
[tex] -2*x+5*0=-20 [/tex]
[tex] -2*x=-20 [/tex]
[tex] x=10 [/tex]
therefore
the answer part 2) is
The x-intercept is equal to [tex] 10 [/tex]
Part 3) What is the slope of the line passing through the points [tex] (2, -5) [/tex] and [tex] (4, 1) [/tex]?
we know that
the slope of the line is equal to
[tex] m=\frac{(y2-y1)}{(x2-x1)} [/tex]
Substitute the values in the formula
[tex] m=\frac{(1+5)}{(4-2)} [/tex]
[tex] m=\frac{(6)}{(2)} [/tex]
[tex] m=3 [/tex]
therefore
the answer part 3) is
The slope of the line is equal to [tex] 3 [/tex]
Part 4) Select all statements that are true about the linear equation.
[tex] y = 4x- 3 [/tex]
Statements
a) The graph of the equation is the set of all points that are solutions to the equation
This statements is True------> Any point that belongs to the graph of the equation is the solution to the equation
b) The point [tex] (0,-3) [/tex] is on the graph of the equation
substitute the values in the equation
[tex] -3 = 4*0- 3 [/tex]
[tex] -3 = - 3 [/tex] ----> the point is on the graph of the equation
therefore
This statements is True
c) The point (1, 1) is on the graph of the equation
substitute the values in the equation
[tex] 1 = 4*1- 3 [/tex]
[tex] 1 = 1 [/tex] ----> the point is on the graph of the equation
therefore
This statements is True
d) The graph of the equation is a single point representing one solution to the equation
This statements is False ------> the equation graph are infinite points, representing infinite equation solutions