Each month, a retail store awards a blue ribbon to its employee of the month. The probability that Chloe is the employee of the month is 29% in January and 49% in February. What is the probability that she is awarded a blue ribbon in both January and February?

Respuesta :

1421 / 100 = 14.21% 

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Answer:

[tex]0.1421\ or\ 14.21\%[/tex]

Step-by-step explanation:

The probability that Chloe is the employee of the month in January is 29% or 0.29

i.e [tex]P(J)=0.29[/tex]

The probability that Chloe is the employee of the month in February is 49% or 0.49

i.e [tex]P(F)=0.49[/tex]

As both of the events are independent, so

[tex]P(J\ and\ F)=P(J)\cdot P(F)[/tex]

[tex]=0.29\times 0.49[/tex]

[tex]=0.1421=14.21\%[/tex]

Therefore, the probability that Chloe is awarded a blue ribbon in both January and February is 0.1421 or 14.21%