Respuesta :
Given that there
are 17 portable mini suites (a.k.a. cages) in a row at the Paws and
Claws Holiday Pet Resort. They are neatly labeled with their guests'
names. There are 8 poodles and 9 tabbies. How many ways can the "suites"
be arranged if:
a) there are no restrictions.
Part A:
If there are no restrictions, then the number of ways the "suites" can be arranged is given by:
[tex]17!=17\times16\times15\times14\times13\times12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1=355,687,428,096,000 \ ways[/tex]
Part B:
If cats and dogs must alternate, then the number of ways the "suites" can be arranged is given by:
[tex]9!\times8!=9\times8\times7\times6\times5\times4\times3\times2\times1\times8\times7\times6\times5\times4\times3\times2\times1=14,631,321,600 \ ways[/tex]
Part C:
If dogs must be next to each other, then the group of dogs are taken as 1 object and there are now 10 objects to arrange. The number of ways to arrange 10 objects is given by:
[tex]10!=10\times9\times8\times7\times6\times5\times4\times3\times2\times1=3,628,800 \ ways[/tex]
Also, the group of dogs can be arranged in:
[tex]8!=8\times7\times6\times5\times4\times3\times2\times1=40,320 \ ways[/tex]
Therefore, the total number of ways the "suites" can be arranged is given by:
[tex]10!\times8!=3,628,800\times40,320=146,313,216,000 \ ways[/tex]
Part D:
If dogs must be next to each other and cats must be next to each other, then the group of dogs are taken as 1 object and the group of cats are taken as 1 object, then there are now 2 objects to arrange.
The number of ways to arrange two objects is given by:
[tex]2!=2\times1=2[/tex]
The number of ways the 9 dogs are to be arranged is given by:
[tex]9!=9\times8\times7\times6\times5\times4\times3\times2\times1=362,880[/tex]
The number of ways the 8 cats are to be arranged is given by:
[tex]8!=8\times7\times6\times5\times4\times3\times2\times1=40,320[/tex]
Therefore, the total number of ways the "suites" can be arranged is given by:
[tex]2!\times9!\times8!=2\times362,880\times40,320=29,262,643,200 \ ways[/tex]
b) cats and dogs must alternate.
c) dogs must be next to each other.
d) dogs must be next to each other and cats must be next to each other.
Part A:
If there are no restrictions, then the number of ways the "suites" can be arranged is given by:
[tex]17!=17\times16\times15\times14\times13\times12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1=355,687,428,096,000 \ ways[/tex]
Part B:
If cats and dogs must alternate, then the number of ways the "suites" can be arranged is given by:
[tex]9!\times8!=9\times8\times7\times6\times5\times4\times3\times2\times1\times8\times7\times6\times5\times4\times3\times2\times1=14,631,321,600 \ ways[/tex]
Part C:
If dogs must be next to each other, then the group of dogs are taken as 1 object and there are now 10 objects to arrange. The number of ways to arrange 10 objects is given by:
[tex]10!=10\times9\times8\times7\times6\times5\times4\times3\times2\times1=3,628,800 \ ways[/tex]
Also, the group of dogs can be arranged in:
[tex]8!=8\times7\times6\times5\times4\times3\times2\times1=40,320 \ ways[/tex]
Therefore, the total number of ways the "suites" can be arranged is given by:
[tex]10!\times8!=3,628,800\times40,320=146,313,216,000 \ ways[/tex]
Part D:
If dogs must be next to each other and cats must be next to each other, then the group of dogs are taken as 1 object and the group of cats are taken as 1 object, then there are now 2 objects to arrange.
The number of ways to arrange two objects is given by:
[tex]2!=2\times1=2[/tex]
The number of ways the 9 dogs are to be arranged is given by:
[tex]9!=9\times8\times7\times6\times5\times4\times3\times2\times1=362,880[/tex]
The number of ways the 8 cats are to be arranged is given by:
[tex]8!=8\times7\times6\times5\times4\times3\times2\times1=40,320[/tex]
Therefore, the total number of ways the "suites" can be arranged is given by:
[tex]2!\times9!\times8!=2\times362,880\times40,320=29,262,643,200 \ ways[/tex]