Respuesta :
mass = 2kg
radius = .5 m
v = 3m/s
centripetal force = (mv^2)/r
centripetal force = ((2)(3 ^2))/ .5
= (2 * 3 * 3) / .5
= 36
radius = .5 m
v = 3m/s
centripetal force = (mv^2)/r
centripetal force = ((2)(3 ^2))/ .5
= (2 * 3 * 3) / .5
= 36
Answer:
Centripetal force = 36 N
Explanation:
It is given that,
Mass of an object, m = 2 kg
Radius of circle, r = 0.5 m
velocity of an object, v = 3 m/s
We have to find the centripetal force of that object. When the object moves in a circular path, the force exerted by that object is called its centripetal force. Mathematically, it is given by :
[tex]F_c=\dfrac{mv^2}{r}[/tex]
[tex]F_c=\dfrac{2\ kg\times (3\ m/s)^2}{0.5\ m}[/tex]
[tex]F_c=36\ N[/tex]
Hence, the centripetal force is 36 N.
