Answer:
[tex]\sf 2\dfrac{2}{3}b-2\dfrac{1}{2}[/tex]
Step-by-step explanation:
Simplify the algebraic expression:
[tex]\sf 3b - \dfrac{1}{3}b+2\dfrac{1}{2} = \dfrac{3}{1}b-\dfrac{1}{3}b+2\dfrac{1}{2}[/tex]
Least common denominator of 1 and 3 is 3.
[tex]\sf = \dfrac{3*3}{1*3}-\dfrac{1}{3}b+2\dfrac{1}{2}\\\\\\=\dfrac{9}{3}b - \dfrac{1}{3}b-2\dfrac{1}{2} \ {\bf Now,subtract}\\\\\\=\dfrac{8}{3}b-2\dfrac{1}{2}\\\\\\\text{Convert into mixed fraction}\\\\= 2\dfrac{2}{3}b-2\dfrac{1}{2}[/tex]
