The percent of persons (ages five and older) in each state who speak a language at home other than English is approximately exponentially distributed with a mean of 14.65.

The lambda of this distribution is
0.0682

The probability that the percent is larger than 10.27 is P(x ≥ 10.27) =
The probability that the percent is less than 18.04 is P(x ≤ 18.04) =
The probability that the percent is between 12.65 and 18.65 is P(12.65 ≤ x ≤ 18.65) =