a satellite revolves around the earth in an orbit radius 42000km . find value of g and orbital speed at this height.

Respuesta :

Answer:

g = 0.171 m/s²

v = 2870 m/s

Explanation:

Acceleration due to gravity is:

g = GM / R²

where G is the universal gravitational constant,

M is the mass of the Earth,

and R is the distance from the Earth's center.

Given:

G = 6.67×10⁻¹¹ Nm²/kg²

M = 5.98×10²⁴ kg

R = 4.2×10⁷ + 6.357×10⁶ = 4.84×10⁷ m

Find: g

g = (6.67×10⁻¹¹ Nm²/kg²) (5.98×10²⁴ kg) / (4.84×10⁷ m)²

g = 0.171 m/s²

The centripetal acceleration is equal to the acceleration due to gravity.

v² / R = g

v = √(gR)

v = √(0.171 m/s² × 4.84×10⁷ m)

v = 2870 m/s