A solid cylinder with radius 8 cm and height 2cm is melted to form a solid cone of height 6 cm. find the diameter of the base of the cone.​

Respuesta :

Answer:

To find the diameter of the base of

the cone formed when the solid

cylinder is melted, we can use the

concept of volume conservation.

The volume of the solid cylinder is

equal to the volume of the solid

cone. 1. **Volume of the Cylinder:**

The formula for the volume of a

cylinder is given by: Veylinder = Tr2h

where:-r=8cm (radius of the

cylinder) -h = 2 cm (height of the

cylinder) Substitute the values:

Veylinder =T x 82 x 22. **Volume of

the Cone:** The formula for the

volume of a cone is given by:

Vcone = 3T12h where:-h= 6 cm

(height of the cone) - r is the radius

of the base of the cone - Since the

radius of the cylinder and cone are

the same, let's denote the radius of

the base of the cone as r as well.

Substitute the values and set the

volumes equal:

" x 82 x 2 = 3tr2 x 6 3. *Solve cylinder) Substitute the values:

Veylinder =T x 82 x 22. **Volume of

the Cone:** The formula for the

volume of a cone is given by:

Vcone = 3T h where:-h = 6 cm

(height of the cone)- r is the radius

of the base of the cone - Since the

radius of the cylinder and cone are

the same, let's denote the radius of

the base of the cone as r as well.

Substitute the values and set the

volumes equal:

T x 82 x 2 = 3tr2 x 6 3. *Solve for

r:** 128g = 2tr264 =r2 r = 8 cm 4.

**Diameter of the Base of the

Cone:** The diameter of the base of

the cone is twice the radius:

Diameter=2r=2x8=16 cm

Therefore, the diameter of the base

of the cone formed is 16 cm.