Answer:
0.10
Explanation:
Method 1: Work energy theorem
W = KE
mgμ d = ½ mv²
μ = ½ v² / (gd)
μ = ½ (3.6)² / (9.8 × 6.5)
μ = 0.10
Method 2: Acceleration and kinematics
∑F = ma
-mgμ = ma
a = -gμ
a = -9.8μ
Given:
s = 6.5 m
u = 3.6 m/s
v = 0 m/s
v² = u² + 2as
0² = (3.6)² + 2 (-9.8μ) (6.5)
μ = 0.10
