Respuesta :
Answer:
each lane would have 15 runners, except for the sixth lane which would have 14 runners.
Step-by-step explanation:
To divide the 89 student runners into the six lanes as equally as possible, we need to find the closest number to 89 that is divisible by 6 (the number of lanes).
Dividing 89 by 6 gives us:
89 ÷ 6 = 14 with a remainder of 5
So, 89 student runners can be divided into 6 lanes with 14 runners in each lane, and there will be 5 remaining runners. However, since the coach wants each lane to have as equal a number of runners as possible, we need to distribute the remaining 5 runners as evenly as possible among the lanes.
One way to distribute the remaining runners is to add one extra runner to each of the first five lanes, leaving the sixth lane with the original 14 runners.
So, the distribution of runners in each lane would be:
First five lanes: 14 + 1 = 15 runners each
Sixth lane: 14 runners
Therefore, each lane would have 15 runners, except for the sixth lane which would have 14 runners.
Answer:
5 lanes have 15 students and 1 lane has 14 students
Step-by-step explanation:
There are 89 students and six lanes.
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So in each lane: 89/6 = 14.8333 students.
Here unfortunately some lanes will have more runners than others.
Taking 14.8333 students ≈ 14 students can completely fill those six lanes.
The remaining students are 89 - 14 × 6 = 5 students.
These 5 runners can fill each lanes which makes it:
5 lanes have 15 students and 1 lane has 14 students in it.