lulu109 lulu109
  • 18-08-2017
  • Mathematics
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If x-y doesn't equal 0 then x^2-y^2 / x-y =

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apologiabiology
apologiabiology apologiabiology
  • 18-08-2017
recognize the differnce of 2 perfect squares

a²-b²=(a-b)(a+b)

so
[tex]\frac{x^2-y^2}{x-y}=\frac{(x-y)(x+y)}{x-y}=(\frac{x+y}{1})(\frac{x-y}{x-y})=(x+y)(1)=x+y[/tex]
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