Respuesta :
subsitution
y=3x+2
subsitute (3x+2) for y in other equation
2x+y=-4
2x+(3x+2)=-4
2x+3x+2=-4
5x+2=-4
minus 2 both sides
5x=-6
divide both sides by 5
[tex]x=\frac{-6}{5}[/tex]
subsitute back
[tex]y=3x+2[/tex]
[tex]y=3(\frac{-6}{5})+2[/tex]
[tex]y=\frac{-18}{5}+2[/tex]
[tex]y=\frac{-18}{5}+\frac{10}{5}[/tex]
[tex]y=\frac{-18+10}{5}[/tex]
[tex]y=\frac{-8}{5}[/tex]
[tex]x=\frac{-6}{5}[/tex]
[tex]y=\frac{-8}{5}[/tex]
(x,y)
[tex](\frac{-6}{5},\frac{-8}{5})[/tex]
the solution is [tex](\frac{-6}{5},\frac{-8}{5})[/tex]
that is the first option
y=3x+2
subsitute (3x+2) for y in other equation
2x+y=-4
2x+(3x+2)=-4
2x+3x+2=-4
5x+2=-4
minus 2 both sides
5x=-6
divide both sides by 5
[tex]x=\frac{-6}{5}[/tex]
subsitute back
[tex]y=3x+2[/tex]
[tex]y=3(\frac{-6}{5})+2[/tex]
[tex]y=\frac{-18}{5}+2[/tex]
[tex]y=\frac{-18}{5}+\frac{10}{5}[/tex]
[tex]y=\frac{-18+10}{5}[/tex]
[tex]y=\frac{-8}{5}[/tex]
[tex]x=\frac{-6}{5}[/tex]
[tex]y=\frac{-8}{5}[/tex]
(x,y)
[tex](\frac{-6}{5},\frac{-8}{5})[/tex]
the solution is [tex](\frac{-6}{5},\frac{-8}{5})[/tex]
that is the first option
Answer:
The solution of the system of equations is:
negative 6 over 5 comma negative 8 over 5.
Step-by-step explanation:
We are given a system of linear equations as:
2x + y = −4 ------------(1)
y = 3x + 2------------(2)
Now we solve the system of equations using the substitution method.
i.e. we substitute the value of y in terms of x from equation (2) in equation (1) and find the value of x and y.
i.e.
2x+3x+2= -4
i.e. 5x+2= -4
i.e. 5x= -6
i.e. x= -6/5
Similarly, on putting this value of x in equation (2) we obtain:
y= -8/5
Hence, the solution is:
[tex](-\dfrac{6}{5},-\dfrac{8}{5})[/tex]