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The ages of the 32 recruits in police academy are normally distributed with a mean of 27 with a standard deviation of 2. What percent of the recruits are between ages 23 and 27?

Respuesta :

z scores are   (age - mean) / std dev

= 23 - 27 / 2  = -2  and  27-27 / 2  = 0 

Using the standard normal tables we find the required percentage is 47.73%

                

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