Answer:
Probability of landing cream cheese side up 3 times is tex]\frac{1}{4}[/tex]
Step-by-step explanation:
The probability of getting cheese side up is one half ([tex]\frac{1}{2}[/tex].
And this probability does not depend on the result of the last time you dropped it or the result before that.
So every time you drop a piece of toast the probability of getting cheese side up is one half ([tex]\frac{1}{2}[/tex].
Charlie has already dropped it once (1st time) and it landed on cream cheese side up. So probability for this is 1 because it has already happened.
Next time (2nd time) he drops, the probability of landing cream cheese side up is [tex]\frac{1}{2}[/tex]
When he drops the piece of toast again (3rd time) the probability of landing cheese side up is again [tex]\frac{1}{2}[/tex].
So the probability of landing cream cheese side up 3 times is,
[tex]1*\frac{1}{2} *\frac{1}{2}[/tex]
=[tex]\frac{1}{4}[/tex]
