To calculate the "bottom" area of the falling large droplet, we can consider it as the area of a circle with the given radius. The formula for the area of a circle is A = πr^2. Given the radius r = 2.5 mm, the area can be calculated as follows:
A = π * (2.5 mm)^2
≈ π * 6.25 mm^2
≈ 19.63 mm^2
Now, if we want to calculate how many times greater the "bottom" area is compared to another area, we would need to have a reference for comparison. If you could provide more information or clarify the question, I'd be happy to assist further!
