Answer:
Step-by-step explanation:
How big is the diagonal of a rectangle with a width of 3 and a length of 5?
the diagonal of the rectangle is the hypotenuse of the two congruent right triangles that are formed by tracing it, so we solve with the Pythagorean theorem
c = [tex]\sqrt{a^2+b^2}[/tex]
c = [tex]\sqrt{3^2+5^2}[/tex]
c = [tex]\sqrt{9+25}[/tex]
c = [tex]\sqrt{34}[/tex]
or
c = ≈ 5.8 units
