The weight of a solid in the air is 75N. The weight in liquid is 65N and the weight in water is 50N. Find the up thrust in the liquid and the Relative density of the liquid

Respuesta :

Answer:

10N and 0.4

Explanation:

The difference in weight between when it was in air and when it was in the fluid gives you the magnitude of the buoyant force. In the first case, it is 10N and when it is in water, it is 25N. The buoyant force is the same as the weight of the fluid being displaced and therefore can be calculated as

Force buoyant = density of fluid x volume of object x gravitational acceleration

We first find the volume of the object using the above formula as we will need it to calculate the density of the fluid later on. We do that by taking in the data about when it is submerged in water and also using the fact that water has a density of 1000kg/m^3. We take the gravitational acceleration to be 10m/s^2.

Subsequently, the volume of the object turns out to be 2.5 x 10^-3 m^3.

By using the same formula above we then calculate the density of the fluid as we now know the buoyant force caused due to the fluid and the volume of the object. The density upon calculation is 400kg/m^3.

The relative density is the ratio of the density of the fluid with that of water and therefore is 400:1000 = 0.4