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If a lever is exerting a force on an object of 65 N, and the object was lifted a height of 3.75 m, how much work was done on the object

Respuesta :

audreyn06

Answer: 243.75J

Explanation:

The work done on an object can be calculated using the formula:

W = Fdcosθ, where:

  • W is the work done (J)
  • F is the force applied (N)
  • d is the distance over which the force is applied (m)
  • θ is the angle between the force vector and the direction of displacement (°)

In this case, F = 65N, d = 3.75m, and assuming that the lever is exerting the force in the same direction at which the object is being lifted, θ = 0°. Plugging these values in:

W = Fdcosθ

W = 65 · 3.75 · cos(0)

W = 243.75

Therefore, the work done on the object is 243.75 Joules.

Learn more about work here: brainly.com/question/31343354

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