17. In the coordinate plane, the vertices of triangle PQR are P(-2,-4), Q (2,-1), and R (8,-9)-
a) Prove that AMNO is a right triangle.
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b) Prove that AMNO is not an isosceles triangle.

Respuesta :

Answer:

See below.

Step-by-step explanation:

a)

Slopes of three sides:

m(PQ) = (-1 + 4)/(2 + 2) = 3/4

m(QR) = (-1 + 9)/(2 - 8) = 8/(-6) = -4/3

m(PR) = (-4 + 9)/(-2 - 8) = 5/(-10) = -1/2

Since the slopes of PQ and QR are negative reciprocals, sides PQ and QR are perpendicular.

b)

The triangle is a a right triangle, and angle Q is a right angle.

Side PR is opposite angle Q, so side PR is the hypotenuse.

In a right triangle, the hypotenuse is always longer than the legs.

In a right triangle, the legs may be congruent.

For the triangle to be isosceles, the legs would have to be congruent.

The legs are sides PQ and QR.

length(PQ) = √[(-4)² + (-3)²] = 5

length(QR) = √[(6)² + (-8)²) = 10

Since the lengths of the legs are not equal, the triangle is not isosceles.