A car of mass 3500 kg slows down at a rate of 6.2 m/s squared when approaching a stop sign. What is the magnitude of the net force causing it to slow down

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Answer:

The magnitude of the net force (\(F\)) can be calculated using Newton's second law:

\[ F = m \cdot a \]

where:

- \( F \) is the force,

- \( m \) is the mass,

- \( a \) is the acceleration.

In this case:

- \( m = 3500 \, \text{kg} \) (mass of the car),

- \( a = -6.2 \, \text{m/s}^2 \) (negative because it's slowing down).

\[ F = (3500 \, \text{kg}) \cdot (-6.2 \, \text{m/s}^2) \]

Calculate this to find the magnitude of the net force. The negative sign indicates that the force is acting in the opposite direction to the motion.