Answer:
x = 20/7 , y = -23/21
Step-by-step explanation:
By using the algebraic method ,
2x - 3y = 9 _____ equation(1)
-5x - 3y = -11 _____ equation(2)
If Equation(1) - Equation(2) ,
2x - 3y - (-5x - 3y) = 9 - (-11)
2x - 3y + 5x + 3y = 9+11
7x = 20
Therefore ,
[tex]x \: = \frac{20}{7} [/tex]
So if you get x , you can substitute x in equation (1) or equation (2) . Then you'll get y.
When x = 20/7 in equation(1) ,
[tex](2 \times \frac{20}{7} ) - 3y \: = 9 \\ \frac{40}{7} - 3y = 9 \\ - 3y \: = 9 - \frac{40}{7} \\ - 3y = \frac{23}{7} \\ y = - \frac{23}{21} [/tex]
Therefore, the values x and y are
[tex]x = \frac{20}{7} \\ y = - \frac{23}{21} [/tex]
