Respuesta :

Edufirst
You need to use the specifc latent heat of vaporization of water which you can find in internet.

I found 2,264.76 KJ / kg = 2,264.76 J/g

Now use total heat = specific latent heat * mass

=> 84.8 g * 2,264.76 J/ g = 192,051.65 J.

Answer: 192,051.65 J

Answer: Amount of heat required to vaporize 84.8 g of water is 191.7kJ.

Explanation: We are given 84.8 grams of water, to convert it into moles, we use the formula:

[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Molar mass of water = 18 g/mol

[tex]Moles=\frac{84.8g}{18g/mol}=4.71moles[/tex]

As we know that [tex]\Delta H_{vap}[/tex] for 1 mole of water at 100° C is 40.7 kJ/mol

So, to calculate the amount of heat required, we use the formula:

[tex]q=m\Delta H_{vap}[/tex]

Putting the values in above equation, we get

[tex]q=4.71mol\times 40.7kJ/mol[/tex]

q = 191.7kJ

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