Multiplicative property of equality states that if a and b are 2 equal expressions, or numbers, then if we multiply both by a non zero expression c, then the results are again equal.
So if a=b, then ac=bc.
The first equality is
(i) [tex] \frac{1}{4}x+ \frac{1}{3}y=5 [/tex]
multiplying both sides by 12, we have:
[tex]12* \frac{1}{4}x+ 12*\frac{1}{3}y=12*5 [/tex]
3x+4y=60
The second equality is
[tex] \frac{1}{2}x+ \frac{3}{2}y=11 [/tex]
multiplying by 2 we get
x+3y=22
Answer: 3x+4y=60; x+3y=22 (the first one only)
