Respuesta :

20joshuagoodin
(4x^3)(2x)^-4=(4x^3) (2^-4)(x^-4)
=(4/16)(x^-1) = 1/4x
The answer is 1/4x

Given: The equation [tex](4x^{3})(2x)^{-4}[/tex]

To Find: The simplified expression

Solution: [tex]\frac{1}{4x}[/tex]

Calculation/Explanation: The equation can be simplified in the follwing way by using the Rules of Exponents.

[tex]4x^{3}(2x)^{-4} \\\\= \frac{4x^{3}}{(2x)^{4}} \\\\=\frac{4x^{3}}{16x^{4}}\\\\=\frac{1}{4}x^{3-4} \\\\=\frac{1}{4}x^{-1}\\\\ =\frac{1}{4x}[/tex]

We have used two Rules of Exponents

  1. For any integer a, [tex]x^{-a}= \frac{1}{x^{a}}[/tex]
  2. And for any integers a, b, [tex]x^{a-b}= \frac{x^a}{x^b}[/tex]

Otras preguntas