Consider the reaction below. 2Al2O3 4Al + 3O2 How many moles of oxygen are produced when 26.5 mol of aluminum oxide are decomposed? 17.7 mol 19.9 mol 39.8 mol 53.0 mol

Respuesta :

Answer : The number of moles of oxygen produced are, 39.8 mole

Solution : Given,

Moles of aluminium oxide = 26.5 mole

The given balanced chemical reaction is,

[tex]2Al_2O_3\rightarrow 4Al+3O_2[/tex]

From the balanced chemical reaction, we conclude that

As, 2 moles of aluminium oxide decomposes to give 3 moles of oxygen

So, 26.5 moles of aluminium oxide decomposes to give [tex]\frac{3}{2}\times 26.5=39.75=39.8[/tex] moles of oxygen

Therefore, the number of moles of oxygen produced are, 39.8 mole

Decomposition is a type of chemical reaction in which the reactants breaks to produce 2 or more product species.

39.8 moles will be produced in the decomposition reaction.

How to calculate the number of moles?

The balanced reaction can be shown as:

[tex]\rm 2 Al_{2}O_{3} \rightarrow 4Al + 3O_{2}[/tex]

Given,

Moles of Aluminium oxide [tex]\rm (Al_{2}O_{3})[/tex] = 26.5 mol

From the reaction, it can be deduced that,

2 moles of [tex]\rm Al_{2}O_{3}[/tex] = 3 moles of oxygen.

So, 26.5 moles of Aluminium oxide = X moles of oxygen

[tex]\begin{aligned} \;\rm X moles &= \dfrac{26.5 \times 3}{2}\\\\&= 39.8 \;\rm moles \end{aligned}[/tex]

Therefore, option C. 39.8 moles of oxygen will be produced.

Learn more about decomposition reaction here:

https://brainly.com/question/4037817