3 mol of O₂
The Balance chemical equation is as follow,
2 KClO₃ → 2 KCl + 3 O₂
According to this equation on decomposition 2 moles of Potassium chlorate (KClO₃) produces 2 moles of Poatassium chloride (KCl) and 3 moles of oxygen gas (O₂).
Therefore, when,
2 moles of KClO₃ produces = 3 moles of O₂
So,
2 moles of KClO₃ will produce = X moles of O₂
Solving for X,
X = (2 mol × 3 mol) ÷ 2 mol
X = 3 mol of O₂
Using above method you can calculate any amount of O₂ or KCl produced by decomposing any amount of KClO₃.
The reaction in which the reactants splits or break to produce two or more products is called the decomposition reaction.
3 moles of oxygen will be produced.
The balanced reaction can be shown as:
[tex]\rm 2 KClO_{3} \rightarrow 2 KCl + 3 O_{2}[/tex]
According to the reaction, 2 moles of Potassium chlorate [tex]\rm (KClO_{3})[/tex] decomposes to form:
So when 2 moles of [tex]\rm KClO_{3}[/tex] produces = 3 moles of [tex]\rm O_{2}[/tex]
Then,
2 moles of [tex]\rm KClO_{3}[/tex] will produce = X moles of [tex]\rm O_{2}[/tex]
[tex]\begin{aligned}\rm X &= \dfrac{2 \;\rm mol \times 3 \;\rm mol }{ 2 \;\rm mol}\\\\&= 3 \;\rm mol\end{aligned}[/tex]
Therefore, option C is correct.
Learn more about decomposition reaction here:
https://brainly.com/question/1183227
