The volume of the solid right pyramid is equal to 192 in³.
Given
Kabir wants to know the volume of a solid right pyramid with a square base.
He uses a ruler to measure the length of the base as 8 inches.
He then measures the slant height to be 5 inches.
The volume of a pyramid is one-third of the product of its altitude and area of the base.
[tex]\rm Area \ of \ the \ base = (8)^3\\\\Area \ of \ the \ base = 64 \ square \ inches[/tex]
Altitude or height is a distance measurement, usually in the vertical or "up" direction, between a reference datum and a point or object.
[tex]\rm (5 )^2 = h^2+ (4 )^2\\\\25 = h^2+16\\\\h^2=25-16\\\\h^2=9\\\\h=3[/tex]
Therefore,
The volume of the pyramid is;
[tex]\rm Volume = \dfrac{1}{3} \times area \times height\\\\Volume = \dfrac{1}{3} \times 64 \times 9\\\\Volume = 64 \times 3\\\\Volume =192[/tex]
Hence, the volume of the solid right pyramid is equal to 192 in³.
To know more about Pyramid click the link given below.
https://brainly.com/question/3565928
