The probability that the locker's combination will have the first digit less than 4 when it is a three-digit combination, and none of the digits are 0, is 1/3. Hence, option B is the right choice.
What is the probability of an event?
The probability of any event A is given as the ratio of the total number of outcomes favorable to event A (n) to the total number of outcomes in the experiment (S).
Therefore, the probability of event A can be written as,
P(A) = n/S.
How to solve the given question?
In the question, we are given information about a locker's combination.
We are being informed that it has a three-digit combination, none of the digits being zero.
We are asked to find the probability that the first digit of the locker combination is less than 4.
We let the event of the first digit of the combination is less than 4 be A.
The number of outcomes favorable to event A (n) = 3 {viz. 1, 2, and 3}
The total number of outcomes for the first digit (S) = 9 {viz. 1, 2, ... , 8, 9}.
Therefore, the probability of event A = n/S = 3/9 = 1/3.
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