John bought a camera on sale that normally costs $160. If the price was reduced 20% during the sale, what was the sale price of the camera?

(A) $120
(B) $124
(C) $128
(D) $140

Please explain to me how to get the answer.

There are two ways to get the answer of 128

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Method 1

sale price = (original price) - (20% of original price)
sale price = 160 - (20% of 160)
sale price = 160 - (0.2*160)
sale price = 160 - 32
sale price = 128

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Method 2

Sale price = 80% of original price
Sale price = 0.8*(original price)
Sale price = 0.8*(160)
Sale price = 128

The discount is 20% so the leftover bit (80%) is the sale price

John bought a camera on sale that normally costs $160. If the price was reduced 20% during the sale, what was the sale price of the camera?(A) $120(B) $124(C) $128(D) $140Please explain to me how to get the answer.

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John bought a camera on sale that normally costs $160. If the price was reduced 20% during the sale, what was the sale price of the camera?

(A) $120
(B) $124
(C) $128
(D) $140

Please explain to me how to get the answer.