Respuesta :
x=small bag
y=large bag
5x+3y=260
4x+2y=200
(5x+3y=260)*4 =20x+12y=1040
(4x+2y=200)*5 =20x+10y=1000
subtract two equations: 2y=40
divide: y=20
plug y in 5x+3*20=260
simplify x=40
small bag=$40
large bag=$20
y=large bag
5x+3y=260
4x+2y=200
(5x+3y=260)*4 =20x+12y=1040
(4x+2y=200)*5 =20x+10y=1000
subtract two equations: 2y=40
divide: y=20
plug y in 5x+3*20=260
simplify x=40
small bag=$40
large bag=$20
5s + 3l = 260.....multiply by 2
4s + 2l = 200.....multiply by -3
----------------
10s + 6l = 520...result of multiplying by 2
-12s - 6l = -600...result of multiplying by -3
----------------add
-2s = - 80
s = -80/-2
s = 40 <==== small bags
5s + 3l = 260
5(40) + 3l = 260
200 + 3l = 260
3l = 260 - 200
3l = 60
l = 60/3
l = 20 <== large bags
ok....did u write the question correctly ? because I am getting small bags costing more then the large ones.
4s + 2l = 200.....multiply by -3
----------------
10s + 6l = 520...result of multiplying by 2
-12s - 6l = -600...result of multiplying by -3
----------------add
-2s = - 80
s = -80/-2
s = 40 <==== small bags
5s + 3l = 260
5(40) + 3l = 260
200 + 3l = 260
3l = 260 - 200
3l = 60
l = 60/3
l = 20 <== large bags
ok....did u write the question correctly ? because I am getting small bags costing more then the large ones.