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Suppose that a dominant allele (M) codes for marbled patches of fur and a recessive allele (m) codes for solid fur. If a marbled-patched heterozygous individual mates with a solid fur individual, what's the probability of the phenotype and genotype combinations of the offspring? A. 50 percent chance of marbled fur and 50 percent chance of solid fur (50 percent MM; 50 percent mm) B. 25 percent chance of marbled fur and 75 percent chance of solid fur (25 percent MM; 50 percent Mm; 25 percent mm) C. 50 percent chance of marbled fur and 50 percent chance of solid fur (50 percent Mm; 50 percent mm) D. 75 percent chance of marbled fur and 25 percent chance of solid fur (75 percent Mm; 25 percent mm)

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kjade2002
The answer is C. Th genotypic ratio is 50% Mm 50% mm. Th phenotypic ratio is 50% marbled 50% solid

Answer:

Option C, 50 percent chance of marbled fur and 50 percent chance of solid fur (50 percent Mm; 50 percent mm)

Explanation:

Given ,

a) Male is heterozygous marbled-patched individual

b) Female is  solid fur individual

The genotype of the parents would be

a) Male - Mm

b) Female - mm

When these two adult mate , the following offsprings are produced

Mm x mm

Mm, Mm, mm, mm

Thus, offsrpings with Mm genotype will be heterozygous marbled-patched

while the offsrpings with mm genotype will be homozygous solid fur individual

So the ratio  of percent chances of occurrence of Marbled fur to Solid fur is

50 %: 50%

Hence the correct answer is option C