the ratio of surface areas of two similar solids is equal to the square root of the ratio between their corresponding edge lengths. true or false

Respuesta :

Answer:

False.

Step-by-step explanation:

Let us consider two similar cuboids A and B as shown in the figure below.

We have that,

'A' has length, width and height 5, 3 and 4 units respectively.

'B' has length, width and height 7.5, 4.5 and 6 units respectively.

Also, surface area of a cuboid = 2 × ( L + W + H ), where L= length, W= width and H= height.

Now, we will find the surface area of A and B.

Surface area of A, [tex]S_{A}[/tex] = 2 × ( 5 + 3 + 4 ) = 2 × 12 = 24

Surface area of B, [tex]S_{B}[/tex] = 2 × ( 7.5 + 4.5 + 6 ) = 2 × 18 = 36

Therefore, the ratio of the surface area is [tex]S_{A}[/tex] : [tex]S_{B}[/tex] = 24 : 36 = 2 : 3.

Moreover, the ratio of square root of lengths is given by [tex]\sqrt{L_{A}} : \sqrt{L_{B}} = \sqrt{5} : \sqrt{7.5}[/tex] = 2.24 : 2.74

Hence, we see that the ratio of the surface area of two similar solids is not equal to the square root of the ratio between their corresponding edge lengths.

Ver imagen wagonbelleville

Answer:

false

Step-by-step explanation:

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