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The pressure of 5.00 L of gas increases from 1.50 atm to 1240 mmHg. What is the final volume of the gas, assuming constant temperature?

Respuesta :

mergl
(P1)(V1)=(P2)(V2)
(1.50)(5.00)=(1240/760)(V2)
(7.5)/(1240/760)=V2
V2=4.596774194 L
sebassandin

Answer:

[tex]V_2=4.60L[/tex]

Explanation:

Hello,

In this case, by means of the Boyle's law which allows us to understand a gas' volume-pressure relationship through an inversely proportional relationship:

[tex]P_1V_1=P_2V_2[/tex]

We solve for the final volume [tex]V_2[/tex] as required, including the conversion from mmHg to atm for the final pressure:

[tex]V_2=\frac{P_1V_1}{P_2} =\frac{1.50atm*5.00L}{1240mmHg*\frac{1atm}{760mmHg} } \\\\V_2=4.60L[/tex]

Regards.

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