Container A has radius r and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h . What is the maximum amount of water that container B can hold?

Set an equation:

[tex] \pi r^{2} h[/tex]=44
divide both sides by 3.14
[tex] r^{2} h[/tex]=14

[tex] \pi (2.5r)^{2} 4h=x[/tex]
divide both sides by 6.25, 4, and 3.14
[tex] r^{2} h[/tex]=x/78.5

Since these two equations are equal, we can set them up that way.

x/78.5=14
multiply both sides by 78.5
x=1099

Answer: The maximum amount of water that container B can hold is 1,099 ounces.

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TheHero TheHero · Answer 2 · 2017-06-18T15:06:19+02:00

TheHero TheHero

18-06-2017

pi r^2 h = 44
pi (2.5r)^2 * (4h) = Volume of water = V
V = (2.5)^2 *4 * pir^2h = (2.5)^2 *4 * 44 = 1100

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Container A has radius ​r​ and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h . What is the maximum amount of water that container B can hold?

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Container A has radius r and height h . It holds a maximum of 44 ounces of water. Container B has radius 2.5r and height 4h . What is the maximum amount of water that container B can hold?