Respuesta :
v=4,000 ml
M(AgNO₃)=170 g/mol
m(AgNO₃)=17.00 g
n(AgNO₃)=m(AgNO₃)/M(AgNO₃)
c=n(AgNO₃)/v=m(AgNO₃)/{vM(AgNO₃)}
c=17.00/{4,000*170}=2.5*10⁻⁵ mol/L≈0.03 mmol/L
M(AgNO₃)=170 g/mol
m(AgNO₃)=17.00 g
n(AgNO₃)=m(AgNO₃)/M(AgNO₃)
c=n(AgNO₃)/v=m(AgNO₃)/{vM(AgNO₃)}
c=17.00/{4,000*170}=2.5*10⁻⁵ mol/L≈0.03 mmol/L
Answer: 0.03 M
Explanation: Molarity of a solution is number of moles of solute dissolved per liter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]Moles=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{17g}{170g/mol}=0.1moles[/tex]
[tex]V_s[/tex] = volume of solution in ml = 4000 ml
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.11mole\times 1000}{4000ml}=0.03mole/L[/tex]
Therefore, the molarity of solution will be 0.03M.
