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A ball is thrown vertically upwards at 19.6 m/s. for its complete trip (up and back down to the starting position), its average velocity is

Respuesta :

scme1702
The average velocity of an object is given by:
Average velocity = total displacement / total time

First, we calculate the time taken to reach the maximum height of the ball. This occurs when the final velocity is 0.
Vf = Vi + at
0 = 19.6 - 9.81 * t
t = 2 seconds

The total trip will be of 4 seconds (2 seconds up, 2 seconds down)

The total displacement is given by:
s = ut + 1/2 * at²
s = 19.6 * 2 - 0.5 * 9.81 * 2²
s = 19.6 meters

This is the distance maximum height, so the total height is
19.6 * 2 = 39.2 meters

Average velocity = 39.2 / 4
Average velocity = 9.8 m/s

[tex]\rm Average \; velocity =9.8\;m/sec[/tex]

Step by Step Solution :

Given :

A ball is thrown vertically upwards at 19.6 m/s.

Calculation :

We know that,

[tex]\rm v = u +at[/tex]

Now,

[tex]0=19.6-9.81t[/tex]

t = 2 sec

Therefore, total trip of 4 seconds (2 sec up and 2 sec down)

We also know that, displacement

[tex]\rm s = ut+\dfrac{1}{2}at^2[/tex]

[tex]\rm s = 19.6\times 2 -0.5\times 9.81\times (2)^2=19.6\;m[/tex]

Therefore total height = 2s

Total height = 39.2 m

[tex]\rm Average \; velocity = \dfrac{39.2}{4}=9.8\;m/sec[/tex]

For more information, refer the link given below

https://brainly.com/question/862972?referrer=searchResults

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