The solution for the polynomial [tex]0=0.25x^2-8x[/tex] is [tex]x=\dfrac{-(-8)\pm \sqrt{(-8)^2)-4(0.25)(0)}}{2\times 0.25}[/tex].
The given quadratic polynomial can be re-written as
[tex]0.25x^2-8x+0=0[/tex].
Compare with the standard quadratic polynomial,
[tex]a=0.25\\b=-8\\c=0[/tex]
Substitute the values of the parameters in [tex]x=\dfrac{-b\pm \sqrt {b^2-4ac}}{2a}[/tex] as-
[tex]x=\dfrac{-b\pm \sqrt {b^2-4ac}}{2a}\\x=\dfrac{-(-8)\pm \sqrt{(-8)^2)-4(0.25)(0)}}{2\times 0.25}[/tex]
Hence, option C is correct.
Learn more about quadratic polynomial here:
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