First, we calculate the moles of ammonium nitrate:
Moles = mass / molecular mass
Moles = 128.4 / 80
Moles = 1.60
From the equation, it is visible that the molar ratio between ammonium nitrate and water is 1 : 2. The moles of water formed will be:
1.6 * 2 = 3.2 moles
Next, we may apply the ideal gas law equation to find the volume:
PV = nRT
V = nRT/P
V = (3.2 * 0.082 * 314)/1.89
V = 43.6 liters
43.6 liters of water will be produced
