[tex]\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\qquad
\begin{cases}
r=radius\\
h=height\\
-----\\
h=15\\
V=1004.8
\end{cases}\implies 1004.8=\cfrac{\pi r^2 15}{3}
\\\\\\
3\cdot 1004.8=15\pi r^2\implies \cfrac{3\cdot 1004.8}{15\pi }=r^2\implies \sqrt{\cfrac{3\cdot 1004.8}{15\pi }}=r[/tex]
