Respuesta :
The equation given as p varies directly with d and inversely with the square root of u is written as:
p = k1d
k1 is the proportionality constant.
and p = k2[tex]\frac{1}{ \sqrt{u} } [/tex]
here k2 is the proportionality constant.
Thus,
combining both equations we get, p = C[tex] \frac{d}{ \sqrt{u} } [/tex]
where K = K1*K2, K is the proportionality constant.
p = k1d
k1 is the proportionality constant.
and p = k2[tex]\frac{1}{ \sqrt{u} } [/tex]
here k2 is the proportionality constant.
Thus,
combining both equations we get, p = C[tex] \frac{d}{ \sqrt{u} } [/tex]
where K = K1*K2, K is the proportionality constant.
P varies directly proportional with d and inversely proportional with the square root of u in your equation. Then the equation is
[tex]\rm P = k\dfrac{d}{\sqrt{u}}[/tex].
What are ratio and proportion?
A ratio is an ordered couple of numbers a and b, written as a/b where b can not equal 0.
A proportion is an equation in which two ratios are set equal to each other.
An equation that expresses the following relationship. P varies directly proportional with d and inversely proportional with the square root of u in your equation.
P varies directly proportional with d that is given by
[tex]\rm P \propto d[/tex] ...1
P varies inversely proportional with the square root of u that is given by
[tex]\rm P \propto \dfrac{1}{\sqrt{u}}[/tex] ...2
From equations 1 and 2, we have
[tex]\rm P \propto \dfrac{d}{\sqrt{u}}\\[/tex]
Whenever the proportionality is removed then a constant comes.
[tex]\rm P = k\dfrac{d}{\sqrt{u}}[/tex]
Where, k is proportionality constant.Thus, the equation is
[tex]\rm P = k\dfrac{d}{\sqrt{u}}[/tex].
More about the ratio and proportion link is given below.
https://brainly.com/question/14335762