Answer: [tex]9\sqrt{2}[/tex]
Step-by-step explanation:
The given expression: [tex]\sqrt{8}+3\sqrt{2}+\sqrt{32}[/tex]
We know that
[tex]\sqrt{8}=\sqrt{2\times2\times2}\\\\=\sqrt{2^2\times2}\\\\=2\sqrt{2}[/tex]
[tex]\sqrt{32}\\\\=\sqrt{2\times2\times2\times2\times2}\\\\=\sqrt{4^2\times2}\\\\=4\sqrt{2}[/tex]
Now, substitute the value of [tex]\sqrt{8}[/tex] and [tex]\sqrt{32}[/tex] in the given expression , we get
[tex]2\sqrt{2}+3\sqrt{2}+4\sqrt{2}\\\\=9\sqrt{2}[/tex]
